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addressable    音标拼音: [ədr'ɛsəbəl]
a. 可设定位址的



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  • difference between addressable and address in memory?
    Assume the memory is 4-byte addressable MY QUESTION IS: what is the difference between an "address" and "the memory is 4 byte addressable"? I understand an address would be its location in memory that is represented by bits, such as 2^n, where n is the number of bits in the address
  • What is the maximum directly adddressable memory capacity?
    Consider a 32-bit microprocessor composed of 2 fields: the first byte contains the opcode and remainder an immediate operand or an operand address What is the maximum directly addressable memory capacity? Now the answer should be 2^24=16777216 bits = 2 megabytes but the solution set says 2^24=16 MBytes So am I wrong or is the solution set wrong?
  • computer architecture - Word- or byte-addressable? Correct terminology . . .
    Page-addressable, block-addressable? Bit-addressable, byte-addressable and word-addressable are the only terms I've seen use It doesn't make much sense to address only units bigger than the word at the architectural level Word-addressable is nowadays only used for special purpose processors such as DSP
  • Byte addressable vs Word addressable - Computer Science Stack Exchange
    I am trying to understand the difference between byte addressing and word addressing A 4-way set-associative cache memory unit with a capacity of 16 KB is built using a block size of 8 words Th
  • computer architecture - Advantage of byte addressable memory over word . . .
    With byte addressable memory and a 32 bit address you can have 4GB while with word addressable memory you can have 4GB * wordsize Are single bytes used that much that you can't use routines that filter out single bytes from a word because there is an advantage of having more memory?
  • How can memory size be 1M x 16? - Computer Science Stack Exchange
    Bits in an addressable memory location - 16 in this example Addressable memory locations - 1M = 2^20 in this example CPU word size 1M = 2^20, while the max number of memory locations for 16 bits is 2^16 How could there be a memory size of 1M x 16? 16-bit CPU with memory locations 16-bits wide and a 20-bit segmented architecture like the 8086
  • computer architecture - Does word addressable memory have more bytes . . .
    1 Well, my question - if word addressable memory has more bytes than byte addressable memory - is derived from the fact that in word addressable memory each address addresses a word and in byte addressable memory each address addresses a byte
  • How to calculate the number of tag, index and offset bits of different . . .
    Let's assume the system is byte addressable Then each cache block contains 8 words* (4 bytes word)=32=2 5 bytes, so the offset is 5 bits The index for a direct mapped cache is the number of blocks in the cache (12 bits in this case, because 2 12 =4096 ) Then the tag is all the bits that are left, as you have indicated
  • Why does a 32 bit address only contain 1 byte, when 32 bits = 4 bytes?
    The question is confusingly worded, but if the question is "why a pointer of 32 bits (4 bytes) points to only one byte of storage", that is just how a particular computer architecture (like x86) is designed It's designed with byte-addressable storage, even though the address space itself is larger than 8 bits, and therefore a pointer into that address space requires more than one byte for its
  • How many words of memory map to the same cache entry?
    0 I am going over some practice questions for the Major field exam and it asks: A processor with a word-addressable memory has a two-way set-associative cache A cache line is one word, so a cache entry contains a set of two words If there are M words of memory and C cache entries, how many words of memory map to the same cache entry?





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