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  • Consider the diagram and proof by contradiction.
    Explanation To prove the angles ∠B and ∠C are congruent in triangle ABC, we start with the given information: AB ≅ AC This congruence means that the lengths of sides AB and AC are equal, which we can write as AB = AC Next, we make an assumption for the sake of proof by contradiction
  • Figure ABCD is a square. Prove BD ≅ AC. - Brainly. com
    To prove that the diagonals of square ABCD, denoted as BD and AC, are congruent (BD ≅ AC), let's examine the statements and reasons provided in the proof: ABCD is a square: This is given in the problem statement
  • [FREE] What is the apparent power of an AC circuit with a source . . .
    The apparent power of the AC circuit is calculated using the formula S = V × I Substituting the given values of voltage (120V) and current (6A) yields an apparent power of 720 volt-amps Thus, the correct choice is D 720
  • [FREE] In the diagram below, $\angle BAC=24^\circ$ and $AB=AC$. If . . .
    In triangle ABC, since AB = AC, the angles opposite these sides are equal Using the angle sum property of triangles, we determined that y = 78 degrees Therefore, the value of y is 78 degrees
  • AC is tangent to circle B. The measure of ∠ACB is 58°. What is the . . .
    To find the measure of m∠ABC in the given circle with tangent AC at circle B and given m∠ACB = 58°, we can use the property that the angle formed between a tangent to a circle and a radius drawn to the point of tangency is called the tangent-secant theorem
  • Given: AB II DE, AC = CE - brainly. com
    The segments AC and CE are equal (i e , AC = CE) Use properties of parallel lines: Since AB ∥ DE, by the Corresponding Angles Postulate, we know that: ∠B AC = ∠CE D (corresponding angles) ∠ABC = ∠C DE (corresponding angles) Identify the third angle relation: In triangles, the sum of angles is always 180 degrees
  • [FREE] Given: BC = EF Prove: AC gt; EF 1. BC = EF 1. Given - brainly. com
    AC = AB + BC Since B is between A and C, this means AC is always greater than BC, therefore: AC> BC Substituting the Value of BC: We know from the given information that BC = EF Therefore, we can substitute EF in for BC in our inequality: AC> EF Thus, we have proven that AC > EF by showing that AC is greater than BC and substituting BC with EF
  • [FREE] Two boats start their journey from the same point A and travel . . .
    To find the distance CD between the two boats traveling along directions AC and AD from a common starting point A, we can use the law of cosines Let's denote the angles and the distances respectively
  • Consider the right triangular prism given AC = 9 cm and AD = 10 cm . . .
    Given AC = 9 cm and AD = 10 cm, it looks like a suggestion that AC and AD form a right triangle's sides We can use this to determine the base of the triangle, which is crucial for further parameters of the prism While it's not explicitly mentioned, it's often assumed that in right triangular prisms, the triangle itself is the base
  • Determine each segment length in the right triangle ABC with a right . . .
    If side AC is the hypotenuse of right triangle ABC, and we have one leg AD labeled 7, we are missing the length of the other leg BC (assuming it's a right angle at B) To find the length of BC, we use the Pythagorean theorem which states c = √ (a² + b²) Here c is the hypotenuse which is labeled 14 and a is one segment labeled 7





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